Quant Quiz

Q1. Bhavika alone would take 8 h more to complete the job than when Bhavika and Rita worked together. If Rita worked alone, she would take 4½ hrs more to complete the job than when Bhavika and Rita worked together. What time would they take if both Bhavika and Rita worked together ?
(1) 5 days 
(2) 4 days
(3) 3 days 
(4) 6 days
(5) None of these

Q2. If 36 men can dig a trench 200 m long, 3 m wide and 2 m deep in 6 days working 10 h a day, in how many days, working 8 h a day will 10 men dig a trench 100 m long, 4 m wide and 3 m deep ?
(1) 15 days
(2) 27 days
(3) 20 days
(4) 54 days
(5) None of these

Q3. A train can travel 20% faster than a car. Both start from the point A at the same time and reach point B, 75 km away from A at the same time. On the way however the train lost about 12.5 min while stopping at the stations. The speed of the car is
(1) 50 km/h 
(2) 55 km/h
(3) 60 km/h 
(4) 65 km/h
(5) None of these

Q4. Two trains of equal length are running on parallel lines in the same direction at 46 km/h and 36 km/h. The faster train passes the slower train in 36 s. The length of each train is
(1) 50 m 
(2) 80 m
(3) 72 m 
(4) 82 m
(5) None of these

Q5. An automobile financier claims to be lending money at simple interest but he includes the interest every six months for calculating the principal. If he is charging an interest of 10%, the effective rate of interest becomes
(1) 10% 
(2) 10.25%
(3) 10.5% 
(4) 10.35%
(5) None of these

Directions (Q6 – Q10): In each of these questions a number series is given. In each series only one number is wrong. Find out that number.

Q6. 2 12 36 81 150 252
(1) 2 
(2) 81 
(3) 36 
(4) 150 
(5) 252

Q7. 5 16 27 44 65 90
(1) 16 
(2) 5 
(3) 44 
(4) 65 
(5) 90

Q8. 4 2 0 -5 -12 -21
(1) 0 
(2) 4 
(3) 2 
(4) -5 
(5) -21

Q9. 101 123 149 179 218 251
(1) 251 
(2) 123 
(3) 179 
(4) 218 
(5) 101

Q10. 9 21 45 101 211 433 879
(1) 21 
(2) 45 
(3) 211 
(4) 433 
(5) 101

Answers:

Q1 – (4)
Let Bhavika and Rita working together
can finish a job in x days.
Then, in 1 day they will complete = 1/x work
Bhavika working alone do in 1 day = 1/(x+8) work
Rita working alone will do in 1 day = 1/(x+9/2) work
So, 1/(x+8) + 1/(2x+9) = 1/x
=> [(2x+9) + 2(x+8)]/[(x+8)(2x+9)] = 1/x
=> x = 6days

Q2 – (2)
According to Question 
M1 x D1 x T1 x W2 = M2 x D2 x T2 x W1
36 x 6 x 10 x 1200 = 10 x D2 x 8 x 1200
D2 = 36 x 6 x 10 x 1200 / 10 x 9 x 1200 = 27days

Q3 – (3)
Let the speed of the car be x km/h
So, Speed of train = x * 1.2x = 6x / 5 km/h
So, 5/6x * 75 + 25/(2*60) = 75/x
= 75*2*60/6*25 = 60km/h

Q4 – (1)
Let the length of each train be x mtr
Then, total distance covered = (x + x) = 2x mtr
Relative Speed = (46 – 6) = 10 km/h = 10*5/18 m/s
Given (time) 36 = 2x * 18/50

Q5 – (2)
According to question, S.I. on Rs. 100 at 10% for six months 
=(100*10*6)/(100*12) = Rs. 5
Principal for next six months = Rs. 105
SI = 105*10*6/100*12 = Rs. 5.25
Total interest = Rs. 10.25

Q6 – (2)
The series is 1² x 2 = 2, 2² x 3 = 12, 3² x 4 = 36, 4² x 5 = 80 and so on.. Hence, 81 should be replaced by 80.

Q7 – (1)
The series is 1 x (2+3) = 5, 2 x (3+4) = 14, 3 x (4+5) = 27 and so on..
Hence, 16 should be replaced by 14

Q8 – (3) 
The series is 3² – 2² – 1² = 4, 4² – 3² – 2² = 3 and so on..
Hence, 2 should be replaced by 3.

Q9 – (4)
The series is 10² + ² + 0² = 101, 11² + 1² + 1² = 123, 12² + 1² + 2² = 149 and so on..
Hence, 218 should be replaced by 213

Q10 = (2)
The series is x 2 + 3, x 2 + 5, x 2 + 7, x 2 + 9, x2 + 11 and so on..
Hence, 45 should be replaced by 47.

Quant Quiz - Topic: Partnership

Q1)-Three partners A, B , C start a business. Twice A's capital is equal to thrice B's capital and B's capital is four times C's capital . Out of a total profit of Rs. 16,500 at the end of the year, B's share is

Rs 4000

RS 6000

Rs 7500

Rs 6600

Ans.- B
Let C = x. Then B =4x and 2A = 3 X 4x = 12x or A= 6x
A : B : C =6x : 4x :x = 6 : 4 : 1
So B's capital is ( 16500 X 4/11) = Rs 6000

Q2)-If 4 (A's Capital) = 6(B's capital) = 10 (C's capital) , then out of a profit of Rs 4650, C will receive :

Rs 465

Rs 900

Rs 1550

Rs 2250

Ans.- B
LEt 4A = 6B = 10C = k
Then, A : B : C = k/4 : k/6 : k/10 = 15 : 10 : 6
Hence , C's share = rs ( 4650 X 6/31) = Rs 900

Q3)-A , B and C enter into partnership. A invests some money at the beginning , B invests double the amount after 6 months and C invests thrice the amount after 8 months If the annual profit be Rs 27000, C's share is

Rs 8625

Rs 9000

Rs 10800

Rs 11250

Ans.- B
Let A's investment be Rs x.
Then, Ratio of capitals = (x X 12) : (2x X 6) : (3x X 4)= 1 : 1 : 1
C's Share = Rs ( 27000 X 1/3) =Rs 9000

Q4)-A, B , C hired a car for Rs 520 and used it for 7 , 8 and 11 hours respectively. Hire charges paid by B were

Rs 140

Rs 160

Rs 180

Rs 220

Ans.- B
A : B : C = 7 : 8 : 11
Hire charges paid by B = Rs ( 520 X 8/26) =RS 160

Q5)-A , B and C rent a pasture. A puts 10 oxen for 7 months , B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing. If the rent of the pasture is Rs 175. How much must C pay as his share of rent ?

Rs 45

Rs 50

Rs 55

Rs 60

Ans.- A
A : B : C = 10 x 7 : 12 x 5 : 15 x 3= 14 : 12 :9
C's rent= Rs ( 175 x 9/35) =rs 45

Q6)-In a business A and C invested amounts in the ratio 2 : 1 , whereas the ratio between amounts invested by A and B was 3 : 2. If Rs 157300 was their profit, how much did B receive ?

Rs 24200

Rs 36300

Rs 48400

Rs 72600

Ans.- C
A : B = 3 : 2
B : A = 2 : 3 = 4 : 6 and A : C = 2 : 1 = 6 : 3
So , B : A : C = 4 : 6 : 3
B's share = Rs ( 157300 x 4/13 ) = Rs 48400

Q7)-A and B started a partnership business investing some amount in the ratio of 3 : 5. C joined them after six months with an amount equal to that of B. In what proportion should the profit at the end of one year be distributed among A , B and C ?

3 : 5 : 2

3 : 5 :5

6 : 10 : 5

Data inadequate

Ans.- C
Let the initial investments of A and B be 3x and 5x
A : B : C= (3x X 12) : (5x X 12): (5x X 6) = 6 : 10 : 5

Q8)-A, B and C enter into a partnership and their shares are in ratio 1/2 : 1/3 : 1/4 After 2 months , A withdraws half of his capital and after 10 months , a profit of Rs 378 is divided among them. What is B's share ?

Rs 129

Rs 144

Rs 156

Rs 168

Ans.- B
Ratio of initial investments = 1/2 : 1/3 : 1/4 = 6 : 4 : 3
Let their initial investments be 6x , 2x and 3x respectively.
A : B : C = ( 6x X 2 + 3x X 10 ) : (4x X 12) : ( 3x X 12) = 42 : 48 : 36 = 7 : 8 : 6
B's share = Rs ( 378 x 8/21) =Rs 144

Q9)-A , B and C enter into a partnership in the ratio 7/2 : 4/3 : 6/5. After 4 months , A increases his share by 50 % . If the total profit at the end of one year be Rs 21600. then B's share in the profit is

Rs 2100

Rs 2400

Rs 3600

Rs 4000

Ans.- D
Ratio of initial investments = 7/2 : 4/3 : 6/5 = 105 : 40 : 36
Let the initial investments be 105x , 40x and 36x
A : B : C= ( 105x X 4 + 150/100 X 105x X 8) : (40x X 12) : (36x X 12)
=35 : 10 : 9
Hence, B's share = Rs (21600 X 10/54) =Rs 4000

Q10)-A, B , C started a business with their investments in the ratio 1 : 3 : 5. After 4 months, A invested the same amount as before and B as well as C withdrew half of their investments . The ratio of theirs profits at the end of the year is

4 : 3 : 5

5 : 6 : 10

6 : 5 : 10

10 : 5 : 6

Ans.- B
Let their initial investments be x , 3x and 5x respectively. Then, A: B : C= ( x X 4 + 2x X 8) : (3x X 4 + 3x/2 X 8) : (5x X 4 + 5x/2 X 8)
5 : 6 :10

Quant Quiz - Topic: Partnership

Q1)-Three partners A, B , C start a business. Twice A's capital is equal to thrice B's capital and B's capital is four times C's capital . Out of a total profit of Rs. 16,500 at the end of the year, B's share is

Rs 4000

RS 6000

Rs 7500

Rs 6600

Ans.- B
Let C = x. Then B =4x and 2A = 3 X 4x = 12x or A= 6x
A : B : C =6x : 4x :x = 6 : 4 : 1
So B's capital is ( 16500 X 4/11) = Rs 6000

Q2)-If 4 (A's Capital) = 6(B's capital) = 10 (C's capital) , then out of a profit of Rs 4650, C will receive :

Rs 465

Rs 900

Rs 1550

Rs 2250

Ans.- B
LEt 4A = 6B = 10C = k
Then, A : B : C = k/4 : k/6 : k/10 = 15 : 10 : 6
Hence , C's share = rs ( 4650 X 6/31) = Rs 900

Q3)-A , B and C enter into partnership. A invests some money at the beginning , B invests double the amount after 6 months and C invests thrice the amount after 8 months If the annual profit be Rs 27000, C's share is

Rs 8625

Rs 9000

Rs 10800

Rs 11250

Ans.- B
Let A's investment be Rs x.
Then, Ratio of capitals = (x X 12) : (2x X 6) : (3x X 4)= 1 : 1 : 1
C's Share = Rs ( 27000 X 1/3) =Rs 9000

Q4)-A, B , C hired a car for Rs 520 and used it for 7 , 8 and 11 hours respectively. Hire charges paid by B were

Rs 140

Rs 160

Rs 180

Rs 220

Ans.- B
A : B : C = 7 : 8 : 11
Hire charges paid by B = Rs ( 520 X 8/26) =RS 160

Q5)-A , B and C rent a pasture. A puts 10 oxen for 7 months , B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing. If the rent of the pasture is Rs 175. How much must C pay as his share of rent ?

Rs 45

Rs 50

Rs 55

Rs 60

Ans.- A
A : B : C = 10 x 7 : 12 x 5 : 15 x 3= 14 : 12 :9
C's rent= Rs ( 175 x 9/35) =rs 45

Q6)-In a business A and C invested amounts in the ratio 2 : 1 , whereas the ratio between amounts invested by A and B was 3 : 2. If Rs 157300 was their profit, how much did B receive ?

Rs 24200

Rs 36300

Rs 48400

Rs 72600

Ans.- C
A : B = 3 : 2
B : A = 2 : 3 = 4 : 6 and A : C = 2 : 1 = 6 : 3
So , B : A : C = 4 : 6 : 3
B's share = Rs ( 157300 x 4/13 ) = Rs 48400

Q7)-A and B started a partnership business investing some amount in the ratio of 3 : 5. C joined them after six months with an amount equal to that of B. In what proportion should the profit at the end of one year be distributed among A , B and C ?

3 : 5 : 2

3 : 5 :5

6 : 10 : 5

Data inadequate

Ans.- C
Let the initial investments of A and B be 3x and 5x
A : B : C= (3x X 12) : (5x X 12): (5x X 6) = 6 : 10 : 5

Q8)-A, B and C enter into a partnership and their shares are in ratio 1/2 : 1/3 : 1/4 After 2 months , A withdraws half of his capital and after 10 months , a profit of Rs 378 is divided among them. What is B's share ?

Rs 129

Rs 144

Rs 156

Rs 168

Ans.- B
Ratio of initial investments = 1/2 : 1/3 : 1/4 = 6 : 4 : 3
Let their initial investments be 6x , 2x and 3x respectively.
A : B : C = ( 6x X 2 + 3x X 10 ) : (4x X 12) : ( 3x X 12) = 42 : 48 : 36 = 7 : 8 : 6
B's share = Rs ( 378 x 8/21) =Rs 144

Q9)-A , B and C enter into a partnership in the ratio 7/2 : 4/3 : 6/5. After 4 months , A increases his share by 50 % . If the total profit at the end of one year be Rs 21600. then B's share in the profit is

Rs 2100

Rs 2400

Rs 3600

Rs 4000

Ans.- D
Ratio of initial investments = 7/2 : 4/3 : 6/5 = 105 : 40 : 36
Let the initial investments be 105x , 40x and 36x
A : B : C= ( 105x X 4 + 150/100 X 105x X 8) : (40x X 12) : (36x X 12)
=35 : 10 : 9
Hence, B's share = Rs (21600 X 10/54) =Rs 4000

Q10)-A, B , C started a business with their investments in the ratio 1 : 3 : 5. After 4 months, A invested the same amount as before and B as well as C withdrew half of their investments . The ratio of theirs profits at the end of the year is

4 : 3 : 5

5 : 6 : 10

6 : 5 : 10

10 : 5 : 6

Ans.- B
Let their initial investments be x , 3x and 5x respectively. Then, A: B : C= ( x X 4 + 2x X 8) : (3x X 4 + 3x/2 X 8) : (5x X 4 + 5x/2 X 8)
5 : 6 :10

Quant Quiz - DI Practice

Directions for questions 1 to 5: Answer the questions on the basis of the information given below.

The pie-chart given below represents the percentage wise distribution of students in six different schools.

(Show Graph Above▲)

Question.1. What is the total number of girls in School-C, number of girls in School-E and the number of boys in School-D together?
1) 1700
2) 1900
3) 1600
4) 1800
5) None of these

Question.2. What is the respective ratio between the number of boys in School-C, number of girls in School-B and total number of students in School-E?
1) 45 : 7 : 97
2) 43 : 9 : 97
3) 45 : 7 : 87
4) 43 : 9 : 87
5) None of these

Question.3. What is the difference between the total number of students in School-F and the number of boys in School-E?
1) 820
2) 860
3) 880
4) 900
5) None of these

Question.4. In which school the total number of students (both boys and girls) together are equal to the number of girls in School-E?
1) A
2) B
3) C
4) D
5) F

Question.5. Number of girls in School-A is approximately what percent of the total number of students in School-B?
1) 55
2) 50
3) 35
4) 45
5) 41

Directions for questions6 to 10: Answer the questions on the basis of the information given below.

The bar graph given below shows the number of candidates (in thousands) who qualified in an exam in three different states during the period 2004 to 2009.

(Show Graph Above ▲)

Question.6. If 40% of the candidates who qualified in the exam from state-P in 2009 were females, then what was the sum of the number of male candidates who qualified from State-P in 2009 and the total number of candidates who qualified in the exam from state-R in 2007?
1) 91,000
2) 9.1 lacs
3) 93,000
4) 9.3 lacs
5) None of these

Question.7. What was the respective ratio between the number of candidates who qualified in the exam from state-R in 2008 and the number of candidates who qualified in the exam from state-P in 2004?
1) 11 : 10
2) 9 : 11
3) 11 : 7
4) 11 : 9
5) None of these

Question.8. Total number of candidates who qualified in the exam in 2004 and 2005 together from state-Q was approximately what percentage of total number of candidates who qualified in the exam from all the states together in 2007?
1) 61
2) 65
3) 79
4) 69
5) 74

Question.9. What was the difference between the total number of candidates who qualified in the exam from all the states together in 2006 and the total number of candidates who qualified in the exam from State-P over all the years together?
1) 1.2 lacs
2) 11,000
3) 1.1 lacs
4) 12,000
5) None of these

Question.10. What was approximate percentage decrease in the number of candidates who qualified in the exam from State-Q in 2007 as compared to the previous year?
1) 45
2) 55
3) 50
4) 60
5) 30

Solutions:

Solutions for Question (1 – 5):

Answer.1. 4;
Number of Girls in:

School C = 6000 x 26/100 – 900 = 600
School E = 6000 x 29/100 – 1200 = 540

Required Answer = 660 + 540 + 600 = 1800

Answer.2. 3;
Number of Girls in School B = 6000 x 9/100 – 400 = 140
Number of Students in Schhol E = 6000 x 29/100 = 1740

Hence, Required ratio = 900 : 140 : 1740 = 45 : 7 : 87

Answer.3. 5;
Required difference = 1200 – (6000 x 6)/ 100 = 1200 – 360 = 840

Answer.4. 2;
Number of students in School – B = 6000 x 9/100 = 540
= Number of girls in School E

Answer.5. 5;
Number of Girls in School A = 6000 x 12/100 – 500 = 220
Hence, Required percentage = 220/540 x 100 ~ 41%

Solutions for Question (6 – 10):

Answer.6. 1;
Number of male candidates who qualified from state P in 2009 = 85000 60 /100 = 51000

Hence, Required sum = 51000 + 40000 = 91000

Answer.7. 3;
Required ratio = 55 : 35 = 11 : 7.

Answer.8. 5;
Number of candidates who qualified in 2004 and 2005 together from state Q = (40 + 45) thousands = 85000

Total number of candidates who qualified from all the states in 2007 = (45 + 30 + 40) thousands = 115,000

Required percentage = 85/115 x 100 = 74

Answer.9. 3;
Number of qualified candidates from state P over the
years = (35 + 20 + 25 + 45 + 40 + 85) thousand
= 250 thousand
Total number of qualified candidates in 2006
= (25 + 55 + 60) thousand = 140 thousand
Difference = (250 – 140) thousand = 110 thousand
= 1.10 lacs.

Answer.10. 1;
Percentage decrease = 55 – 30/55 x 100 = 45%

Quant Quiz

Directions (Q1-Q5) : Study the following graph carefully and answer the questions given below:

Number (in thousands) of products manufactured and sold by a company over the years

(See Graph ▲)

Q1. What is the difference between the number of products manufactured by the company in the year 2009 and that in 2008?
a) 4000
b) 5500
c) 3500
d) 4500
e) None of these

Q2. The number of products sold by the company in the year 2004 is what per cent of the number of products manufacturing by it in that year ? (rounded off to two digits after decimals)
a) 71.43
b) 67.51
c) 81.67
d) 56.29
e) None of these

Q3. What is the percent increase in the number of products sold by the company in the year 2006 from the previous year ? (rounded off to two digits after decimals)
a) 19.25
b) 33.33
c) 10.45
d) 42.66
e) None of these

Q4. What is the ratio of the number of products not sold by the company in year 2007 to that sold in the year 2005?
a) 3 : 1
b) 6 : 5
c) 1 : 3
d) 5 : 6
e) None of these

Q5. What is the approximate average number of products manufactured by the company over all the year together?
a) 36550
b) 39480
c) 41220
d) 43330
e) 34420

Directions (Q. 56-60) : What should come in the place of question mark(?) in the following numbers series :

Q6. 4, 18, 48, 100, 180, 294, ?
1) 448 
2) 398 
3) 424 
4) 456 
5) None of these

Q7. 3, 4, 10, 33, 136, 685, ?
1) 3726 
2) 4116 
3) 3928 
4) 4204 
5) None of these

Q8. 7, 8, 12, 21, ?, 62
1) 35 
2) 33 
3) 42 
4) 37 
5) 43

Q9. 7, 8, 24, 105, 361, ?
1) 676 
2) 986 
3) 1068 
4) 828 
5) None of these

Q10. 6, 16, 9, 13, 12, 10, ?, ?
1) 15, 7 
2) 17, 6 
3) 21, 11 
4) 16, 5 
5) None of these





Solutions:

Q1. 5
Solution : No. of products manufactured in 2009 = (52.5) x 10^3
                     No. of products manufactured in 2008 = (47.5) x 10^3
                     Required difference = (52.5 – 47.5) x 10^3 = 5000

Q2. 1
Solution : Req % = (25/35) x 100 = 71.43

Q3. 2
Solution : Req % = [(40 – 30)/30] x 100 = 33.33%

Q4. 3
Solution : Req ratio = (45 – 42.5) : (37.5 – 30) = 2.5 : 7.5 = 1 : 3

Q5. 4
Solution : Req Average = (35 + 37.5 + 42.5 + 45 + 47.5 + 52.5)/6 = 43330

Q6. 1
Trick: 2² x 1, 3² x 2, 4² x 3, 5² x 4…

Q7. 2
Trick: x1 + 1, x2 + 2, x3 + 3, x4 + 4…

Q8. 4
Trick: +1², +2², +3², +4²…

Q9. 2
Trick: 1^4, 2^4, 3^4, 4^4…

Q10. 1
Trick: Two series simultaneously. +3, +3, +3 and -3, -3, -3

Quant Quiz

Directions (Q1-Q5): Answer the questions on the basis of the following information.

In a school having 6400 students, boys and girls are in the ratio 3:5. The students play Badminton, Table Tennis or both the sports. 12% of the boys play only Badminton. 22% of the girls play only Table Tennis. 24% of the total students play only Badminton and the number of boys playing both the sports is six times the number of boys playing only Badminton.

Q1. How many boys play Badminton?
a. 1020
b. 288
c. 960
d. 1708
e. None of these

Q2. How many girls play only Badminton?
a. 288
b. 880
c. 1536
d. 1872
e. None of these

Q3. How many students play Table Tennis?
a. 1260
b. 1232
c. 4800
d. 3600
e. None of these

Q4. The number of girls playing Badminton is what percent of the total number of students playing only Badminton?
a. 38.2%
b. 71.8%
c. 31.2%
d. 78%
e. None of these

Q5. What is the ratio of the number of boys to the number of girls playing both the sports?
a. 23 : 25
b. 12 : 25
c. 12 : 13
d. 25 : 13
e. None of these

Direction (Q6-Q10): What value should come in the place of question mark (?) in the following number series :

Q6. 6, 11, 32, 111, 464, ?
a) 2165 
b) 2205 
c) 2285 
d) 2345 
e) 2375

Q7. 3, 14, 39, 84, 155, ?
a) 236 
b) 258 
c) 264 
d) 272 
e) 278

Q8. 8, 12, 24, 60, 180, ?
a) 480 
b) 510 
c) 630 
d) 720 
e) 780

Q9. 168, 171, 178, 191, 212, ?
a) 243 
b) 247 
c) 251 
d) 254 
e) 257

Q10. 4, 7, 10, 11, 22, 19, 46, ?
a) 33 
b) 35 
c) 37 
d) 39 
e) 41

Answers:

Q1 – Q5:

Q1 – None of these [(288 + 1728) = 2016]

Q2 – None of these [1248 girls]

Q3 – None of these [(1264 + 3600) = 4864]

Q4 – None of these [(1248/1536 x 100) = 81.25%]

Q5 – 12 : 13 [1728 : 1872]

Q6 – Q10:

Q6 – d [Series is ×1+5, × 2 + 10, ×3 + 15, × 4 + 20]
Q7 – b [Series is 1 + 1² + 1³ , 2 + 2² + 2³ , 3 + 3² + 3³]
Q8 – c [Series is × 0.5 + 8, ×1.0 + 12, ×1.5 + 24]
Q9 – a [Series is + 1² + 2, + 2² + 3, + 3² + 4……]
Q10– b [Series 1 => 4, 4+6 = 10, 10 + 12 = 22, 22 + 24 = 26
        Series 2 => 7, 7 + 4 = 11, 11 + 8= 19, 19 + 16 = 35]