Quant Quiz - DI Practice

Directions for questions 1 to 5: Answer the questions on the basis of the information given below.

The pie-chart given below represents the percentage wise distribution of students in six different schools.

(Show Graph Above▲)

Question.1. What is the total number of girls in School-C, number of girls in School-E and the number of boys in School-D together?
1) 1700
2) 1900
3) 1600
4) 1800
5) None of these

Question.2. What is the respective ratio between the number of boys in School-C, number of girls in School-B and total number of students in School-E?
1) 45 : 7 : 97
2) 43 : 9 : 97
3) 45 : 7 : 87
4) 43 : 9 : 87
5) None of these

Question.3. What is the difference between the total number of students in School-F and the number of boys in School-E?
1) 820
2) 860
3) 880
4) 900
5) None of these

Question.4. In which school the total number of students (both boys and girls) together are equal to the number of girls in School-E?
1) A
2) B
3) C
4) D
5) F

Question.5. Number of girls in School-A is approximately what percent of the total number of students in School-B?
1) 55
2) 50
3) 35
4) 45
5) 41

Directions for questions6 to 10: Answer the questions on the basis of the information given below.

The bar graph given below shows the number of candidates (in thousands) who qualified in an exam in three different states during the period 2004 to 2009.

(Show Graph Above ▲)

Question.6. If 40% of the candidates who qualified in the exam from state-P in 2009 were females, then what was the sum of the number of male candidates who qualified from State-P in 2009 and the total number of candidates who qualified in the exam from state-R in 2007?
1) 91,000
2) 9.1 lacs
3) 93,000
4) 9.3 lacs
5) None of these

Question.7. What was the respective ratio between the number of candidates who qualified in the exam from state-R in 2008 and the number of candidates who qualified in the exam from state-P in 2004?
1) 11 : 10
2) 9 : 11
3) 11 : 7
4) 11 : 9
5) None of these

Question.8. Total number of candidates who qualified in the exam in 2004 and 2005 together from state-Q was approximately what percentage of total number of candidates who qualified in the exam from all the states together in 2007?
1) 61
2) 65
3) 79
4) 69
5) 74

Question.9. What was the difference between the total number of candidates who qualified in the exam from all the states together in 2006 and the total number of candidates who qualified in the exam from State-P over all the years together?
1) 1.2 lacs
2) 11,000
3) 1.1 lacs
4) 12,000
5) None of these

Question.10. What was approximate percentage decrease in the number of candidates who qualified in the exam from State-Q in 2007 as compared to the previous year?
1) 45
2) 55
3) 50
4) 60
5) 30

Solutions:

Solutions for Question (1 – 5):

Answer.1. 4;
Number of Girls in:

School C = 6000 x 26/100 – 900 = 600
School E = 6000 x 29/100 – 1200 = 540

Required Answer = 660 + 540 + 600 = 1800

Answer.2. 3;
Number of Girls in School B = 6000 x 9/100 – 400 = 140
Number of Students in Schhol E = 6000 x 29/100 = 1740

Hence, Required ratio = 900 : 140 : 1740 = 45 : 7 : 87

Answer.3. 5;
Required difference = 1200 – (6000 x 6)/ 100 = 1200 – 360 = 840

Answer.4. 2;
Number of students in School – B = 6000 x 9/100 = 540
= Number of girls in School E

Answer.5. 5;
Number of Girls in School A = 6000 x 12/100 – 500 = 220
Hence, Required percentage = 220/540 x 100 ~ 41%

Solutions for Question (6 – 10):

Answer.6. 1;
Number of male candidates who qualified from state P in 2009 = 85000 60 /100 = 51000

Hence, Required sum = 51000 + 40000 = 91000

Answer.7. 3;
Required ratio = 55 : 35 = 11 : 7.

Answer.8. 5;
Number of candidates who qualified in 2004 and 2005 together from state Q = (40 + 45) thousands = 85000

Total number of candidates who qualified from all the states in 2007 = (45 + 30 + 40) thousands = 115,000

Required percentage = 85/115 x 100 = 74

Answer.9. 3;
Number of qualified candidates from state P over the
years = (35 + 20 + 25 + 45 + 40 + 85) thousand
= 250 thousand
Total number of qualified candidates in 2006
= (25 + 55 + 60) thousand = 140 thousand
Difference = (250 – 140) thousand = 110 thousand
= 1.10 lacs.

Answer.10. 1;
Percentage decrease = 55 – 30/55 x 100 = 45%