Question.1. The dimensions of an open box are 52 cm, 40 cm and 29 cm .Its thickness is 2 cm. If 2 of metal used in the box weight 0.5 gm., the weight of the box is:
(a) 8.56 kg
(b) 7.76 kg
(c) 7.756 kg
(d) 6.832 kg
(e) None of these
(a) 8.56 kg
(b) 7.76 kg
(c) 7.756 kg
(d) 6.832 kg
(e) None of these
Question.2. The water in a rectangular reservoir having a base 80 meters by 60 meters is 6.5 meters deep. In what time can the water be emptied by a pipe of which the cross section is a square of side 20 cm, if the water runs through the pipe at the rate of 15 km per hour?
(a) 26 hrs
(b) 52 hrs
(c) 65 hrs
(d) 42 hrs
(e) None of these
(a) 26 hrs
(b) 52 hrs
(c) 65 hrs
(d) 42 hrs
(e) None of these
Question.3. A cubic meter of copper weighing 9000 kilograms is rolled into a square bar 9 meters long. An exact cube is cut off from the bar. How much does it weight?
(a) 444.3 kg.
(b) 333.3 kg.
(c) 222.2 kg.
(d) 455.3 kg.
(e) None of these
(a) 444.3 kg.
(b) 333.3 kg.
(c) 222.2 kg.
(d) 455.3 kg.
(e) None of these
Question.4. A certain fraction is equivalent to 2/5 . If the numerator of the fraction is increased by 4 and the denominator is doubled, the new fraction is equivalent to 1/3 . What is the sum of numerator and denominator of the original fraction?
(1) 49
(2) 35
(3) 28
(4) 26
(5) 21
(1) 49
(2) 35
(3) 28
(4) 26
(5) 21
Question.5. The population of city X increased from 650,000 in 2000 to 700,000 in 2010, and it is projected that the population will increase by the same number from 2010 to 2020. Approximately what is the projected percent increase in population from 2010 to 2020 ?
(1) 7.1%
(2) 7.7%
(3) 8.3%
(4) 14.3%
(5) 15.3%
(1) 7.1%
(2) 7.7%
(3) 8.3%
(4) 14.3%
(5) 15.3%
Question.6. Of the science books in a certain supply room, 40 are on botany, 35 are on zoology, 30 are on physics, 40 are on geology, and 55 are on chemistry. If science books are removed randomly from the supply room, how many must be removed to ensure that 20 of the books removed are on the same science subject?
(1) 81
(2) 79
(3) 96
(4) 85
(5) 100
(1) 81
(2) 79
(3) 96
(4) 85
(5) 100
Question.7. In how many different ways, letters of the word MANPOWER be arranged such that all vowels are together?
(1) 360
(2) 4320
(3) 1440
(4) 2160
(5) 40320
(1) 360
(2) 4320
(3) 1440
(4) 2160
(5) 40320
Question.8. On a certain test, 3 students each had a score of 90, 9 students each had a score of 80, 4 students each had a score of 70, and 4 students each had a score of 60. What was the average (arithmetic mean) score for the 20 students ?
(1) 70.5
(2) 75.0
(3) 75.5
(4) 80.0
(5) 80.5
(1) 70.5
(2) 75.0
(3) 75.5
(4) 80.0
(5) 80.5
Question.9. A worker is paid 320 rupees for each day he works and is fined 40 rupees for each day he is absent, if he works for 5 days in a week of 6 days, his earning in 30 days are:
1) 9400
2) 1400
3) 7800
4) 6880
5) None of these
1) 9400
2) 1400
3) 7800
4) 6880
5) None of these
Question.10. Lallu went to the mall to purchase saree for Rabri. The shopkeeper, Mulayam allows him the successive discounts of 20% and 10% on the saree. Find the single discount equivalent to these successive discounts.
1) 30%
2) 28%
3) 32%
4) 35%
5) None of these
1) 30%
2) 28%
3) 32%
4) 35%
5) None of these
Solutions:
Answer.1.(4);
volume of metal= (52 × 40 × 29 – 48 × 36 ×27) = 13664
Weight of metal = [(13664*0.5)/1000] = 6.832 Kg.
volume of metal= (52 × 40 × 29 – 48 × 36 ×27) = 13664
Weight of metal = [(13664*0.5)/1000] = 6.832 Kg.
Answer.2. (2)
Volume of water = (80 × 60 × 6.5) = 31200 m^3
Area of cross section of the pipe = [(20/100)^2] = 1/25 m^2
Volume of water emptied in 1 hour= [(15*1000)/25]=600 m^3
Time taken to empty the water tank = 31200/600 = 52 hours
Volume of water = (80 × 60 × 6.5) = 31200 m^3
Area of cross section of the pipe = [(20/100)^2] = 1/25 m^2
Volume of water emptied in 1 hour= [(15*1000)/25]=600 m^3
Time taken to empty the water tank = 31200/600 = 52 hours
Answer.3. (2)
Weight =[{(1/9)^1/2}^3]*(9000) = 9000/27= 333.3 kg
Weight =[{(1/9)^1/2}^3]*(9000) = 9000/27= 333.3 kg
Answer.4. (5)
Let the numerator and denominator be 2x and 5x. Now
(2x + 4)/10 = 1/3
X = 3.
Required sum = 2x + 5x = 7x = 21
Let the numerator and denominator be 2x and 5x. Now
(2x + 4)/10 = 1/3
X = 3.
Required sum = 2x + 5x = 7x = 21
Answer.5. (1)
Required percentage = (750000 – 700000)/700000 * 100 = 7.14%
Required percentage = (750000 – 700000)/700000 * 100 = 7.14%
Answer.6. (3)
Number of books to be removed = 19 5 +1 = 96
Number of books to be removed = 19 5 +1 = 96
Answer.7. (2)
Number of arrangements = 3! * 6! = 4320
Number of arrangements = 3! * 6! = 4320
Answer.8. (3)
Total score of students = 3 * 90 + 9 * 80 + 4 * 70 + 4 * 60 = 1510
Required average = 1510/20 = 75.5
Total score of students = 3 * 90 + 9 * 80 + 4 * 70 + 4 * 60 = 1510
Required average = 1510/20 = 75.5
Answer.9. 3; 7800
Answer.10. 2; 72
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