Friday, December 29, 2017

Quant Quiz

Directions (Q1 – Q5) : Each of the questions below consists of a question and two statements numbered I and II given below it. You have have to decide whether the data provided in the statements are sufficient to answer the question. Read the question and both the statements and.
Give answer (1) if the data in statement I alone are sufficient to answer the question, while the data in statement II alone are not sufficient to answer the question.
Give answer (2) if the data in statement II alone are sufficient to answer the question, while the data in statement I alone are not sufficient to answer the question.
Give answer (3) if the data either in statement I alone or in statement II alone are sufficient to answer the question.
Give answer (4) if the data in both the statements I and II together are not sufficient to answer the question.
Give answer (5) if the data in both the statements I and II together are necessary to answer the question.
Q1. What is the annual income of Mr. Krishnamurthy form April 2001 to March 2002 ?
I. The annual income of Mr. Krishnamurthy is 70% more than that of his boss.
II . In April 2001 the income of Krishnamurthy was Rs. 12000 and his income increases by 10% per month.
Q2. What is the area of circular field ?
I. The circumference of the field is x metres.
II. The diameter of the field is y metres.
Q3. What is the speed of boat in still water ?
I. The boat covers a distance of 35 kms in 5 hours in downstream.
II. The boat takes 7 hours to cover the same distance in upstream.
Q4. How many students are there in the class ?
I. The ratio between the number of boys and girls is 5 : 6 respectively.
II. The difference between the numbers of boys and girls is 7.
Q5. What is the amount of earned profit ?
I. On selling the article for Rs. 1740, 20% profit is earned.
II. The cost price of the article is Rs. 1400.
Directions (Q6 – Q10) : What approximate value should come in place of question mark (?) in the folowing questions ?(You are not expected to calculate the exact value.)
Q6. (11.49)^4 = ?
(1) 15544 
(2) 16729
(3) 17430 
(4) 18443
(5) 19031
Q7. (2198 – 1347 – 403) ÷ (159 – 113 – 27) = ?
(1) 15 
(2) 24
(3) 37 
(4) 49
(5) 53
Q8. (825 % of 330) ÷ 507 = ?
(1) 5 
(2) 11
(3) 17 
(4) 23
(5) 27
Q9. √888888 × 1.486 = ?
(1) 1200 
(2) 1000
(3) 1600 
(4) 1400
(5) 800
Q10. 564.666 + 82.5091 × 44.581 – 34.111 = ?
(1) 28450 
(2) 4000
(3) 1600 
(4) 14225
(5) 4210





Answers:
Q1 – (2) 
From statement I, If the. annual income of boss be Rs. x, then Mr. Krishnamurthy’s annual income = 170% of x
But we do not know the value of. x. Hence this statement is not sufficient from
From statement II,
Initial income = Rs. 12000
% Increase = 10% per month
Time = 12 months
Income in May = Rs. 12000 + 10% of 12000 = Rs. (12000 + 1200) = Rs. 13200
Similarly, the income for other months can be calculated.
Q2 – (3) 
From statement I, If the radius of the circular field be r metres, then 2*22/7*r = x
This relation gives us the value of radius.
Area = 22/7 × (Radius)²
Hence, statement I alone is sufficient to
answer the question
From statement II,
Diameter = y
Area = (Diameter/2)²
Hence, statement II alone is also sufficient to answer the question.
Q3 – (5) 
Let the speed of boat in still water be x kmph and that of current be y kmph
Rate upstream = (x – y) kmph
Rate downstream = (x + y) kmph
From statement I,
x + y = 35/5
=> x + y = 7 kmph ….(i)
From statement II,
x – y = 35/7
=> x – y = 5 kmph …(ii)
From combined statements I and II, we can get the required answer.
Q4 – (5) 
From statement I,

Let the number of boys and girls be 5x and
6x respectively.
From statement II,
6x – 5x = 7 => x = 7
5x = 35 and 6x = 42
Clearly, both statement are required to answer the question.
Q5 – (1) 
From statement I,
SP = Rs. 1740
% Profit = 20
CP = 100 x 1740/120 = Rs 1450
Profit = Rs. (1740 – 1450) = Rs. 290
Information in statement II is not required.
Hence, statement I alone is sufficient to answer the question.
Q6 – (3)
Q7 – (2)
(2198 – 1347 – 403)/(159 – 113 -27) = 23.58≈ 24
Q8 – (1)
(330 x 825/100) ÷ 507 = 2722.50 / 507 = 5.369 ≈ 5
Q9 – (4) 
√888888 x 1.486 ≈ 943 x 1.5 = 1414.5 
So, Nearest = 1400
Q10 – (5)
564.666 + 82.5091 x 44.581 – 34.111 ≈ 565 + 82.5 x 45 – 34 = 565 + 3712.5 – 34 = 4243.5 
Approx = 4210

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